| From: | "David G(dot) Johnston" <david(dot)g(dot)johnston(at)gmail(dot)com> |
|---|---|
| To: | Rich Shepard <rshepard(at)appl-ecosys(dot)com> |
| Cc: | "pgsql-general(at)postgresql(dot)org" <pgsql-general(at)postgresql(dot)org> |
| Subject: | Re: Extract only maximum date from column |
| Date: | 2025-12-04 20:03:35 |
| Message-ID: | CAKFQuwZEWkgQeWSB7nqzBjHS8kP7kvouT6jhKvfe_G2e3cJvOQ@mail.gmail.com |
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| Lists: | pgsql-general |
On Thursday, December 4, 2025, Rich Shepard <rshepard(at)appl-ecosys(dot)com>
wrote:
> I want the script to extract only the maximum `next_contact' date and
> haven't learned how to do this from my reading of web sites.
>
> The script:
>
> select p.person_nbr, p.company_nbr, c.next_contact
> from people as p, contacts as c
> where c.next_contact >= '2025-11-01'
> group by p.person_nbr, p.company_nbr, c.next_contact
> order by p.person_nbr, p.company_nbr, max(c.next_contact);
>
> returns all contacts rather than only the latest one.
>
> Is using a sub-select the proper way?
>
I would go with a lateral join subquery of the contracts table. Using an
aggregates to perform ranking is an anti-pattern. You want the contract
ranked first when ordered by contract_date. Either use a window function
to explicitly rank the contracts or use a limit/fetch clause to simply
return the first ordered one.
You also seem to have completely missed joining people to contracts -
suggest using explicit “join” clauses to make that error less likely.
David J.
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