| From: | Rich Shepard <rshepard(at)appl-ecosys(dot)com> |
|---|---|
| To: | "pgsql-general(at)postgresql(dot)org" <pgsql-general(at)postgresql(dot)org> |
| Subject: | Re: Extract only maximum date from column |
| Date: | 2025-12-04 21:39:56 |
| Message-ID: | 54638724-615f-52f-29a6-74e2567b9599@appl-ecosys.com |
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| Lists: | pgsql-general |
On Thu, 4 Dec 2025, David G. Johnston wrote:
> I would go with a lateral join subquery of the contracts table. Using an
> aggregates to perform ranking is an anti-pattern. You want the contract
> ranked first when ordered by contract_date. Either use a window function
> to explicitly rank the contracts or use a limit/fetch clause to simply
> return the first ordered one.
David,
I'm closer, but still missing the proper syntax:
select p.person_nbr, p.company_nbr, c.next_contact
from people as p, contacts as c
join lateral (select max(c.next_contact) as last_contact
where p.person_nbr = c.person_nbr and
last_contact >= '2025-11-01'
)
c on true;
resulting in:
psql:companies-contacted-2025.sql:9: ERROR: aggregate functions are not allowed in FROM clause of their own query level
LINE 3: join lateral (select max(c.next_contact) as last_contact
Regards,
Rich
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