From: | Chao Li <li(dot)evan(dot)chao(at)gmail(dot)com> |
---|---|
To: | Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> |
Cc: | pgsql-hackers(at)lists(dot)postgresql(dot)org |
Subject: | Re: Improve hash join's handling of tuples with null join keys |
Date: | 2025-08-18 02:48:08 |
Message-ID: | 5C5EE031-F086-4353-A17A-DA563CD24DDD@gmail.com |
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Lists: | pgsql-hackers |
> On Aug 16, 2025, at 00:52, Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> wrote:
>
> Chao Li <li(dot)evan(dot)chao(at)gmail(dot)com> writes:
>> With this patch, “isnull” now becomes true because of the change of strict op. Then the outer null join key tuple must be stored in a tuplestore. When an outer table contains a lot of null join key tuples, then the tuplestore could bump to very large, in that case, it would be hard to say this patch really benefits.
>
> What's your point? If we don't divert those tuples into the
> tuplestore, then they will end up in the main hash table instead,
> and the consequences of bloat there are far worse.
I might not state clearly. For this comments, I meant the outer table. For example:
SELECT a.*, b.* from a RIGHT JOIN b on a.id = b.a_id;
Let’s say table a is used to build hash, table b is the outer table.
And say, table b has 1000 tuples whose a_id are NULL.
Before this patch, when fetching such a tuple (a_id is null) from table b, the tuple will be returned to parent node immediately.
With this tuple, all of such tuples will be put into hj_NullOuterTupleStore, and only be returned after all non-null tuples are processed.
My comment was trying to say that if there are a lot of null join key tuples in outer table, then hj_NullOuterTupleStore might use a lot of memory or swap data to disk, which might lead to performance burden. So, I was thinking we could keep the original logic for outer table, and return null join key tuples immediately.
>
>> Based on this patch, if we are doing a left join, and outer table is empty, then all tuples from the inner table should be returned. In that case, we can skip building a hash table, instead, we can put all inner table tuples into hashtable.innerNullTupleStore. Building a tuplestore should be cheaper than building a hash table, so this way makes a little bit more performance improvement.
>
> I think that would make the logic completely unintelligible. Also,
> a totally-empty input relation is not a common situation. We try to
> optimize such cases when it's simple to do so, but we shouldn't let
> that drive the fundamental design.
>
I absolutely agree we should not touch the fundamental design for the tiny optimization, that’s why I mentioned “based on this patch”.
With this patch, you have introduced a change in MultiExecPrivateHash():
else if (node->keep_null_tuples)
{
/* null join key, but we must save tuple to be emitted later */
if (node->null_tuple_store == NULL)
node->null_tuple_store = ExecHashBuildNullTupleStore(hashtable);
tuplestore_puttupleslot(node->null_tuple_store, slot);
}
We can simply added a new flag to HashTable, say named skip_building_hash. Upon right join (join to the hash side), and outer table is empty, set the flag to true, then in the MultiExecPrivateHash(), if skip_building_hash is true, directly put all tuples into node->null_tuple_store without building a hash table.
Then in ExecHashJoinImpl(), after "(void) MultiExecProcNode()" is called, if hashtable->skip_building_hash is true, directly set node->hj_JoinState = HJ_FILL_INNER_NULL_TUPLES.
So, the tiny optimization is totally based on this patch, it depends on the HashTable.null_tuple_store (if you take this comment, then maybe rename this variable) and the new state HJ_FILL_INNER_NULL_TUPLES.
Best regards,
==
Chao Li (Evan)
--------------------
HighGo Software Co., Ltd.
https://www.highgo.com/
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