Re: transactions from PHP - double COMMIT required?

Hi,

I think you should use ROLLBACK if the query cannot be executed.
one can commit only results of the queries that work.
Try ROLLBACK statement.

Mihail

Quoting mikie <mikie(dot)pl(at)gmail(dot)com>:

> Hi,
>
> I have this problem - after sending a query from PHP script with
> BEGIN-COMMIT transaction block that contains an error (e.g. I
> intentionally insert wrong data into the field of "date" type) I get
> an error (which is OK):ERROR: date/time field value out of range.
>
> Now, when I try to DELETE or perform some other query later in the
> same PHP script I receive this error:
> ERROR: current transaction is aborted, commands ignored until end of
> transaction block
>
> I am 100% sure that I have closed the transaction block with
> "COMMIT;". When I do the same in the console (psql) I get something
> like:
>
> BEGIN; INSERT INTO table1 (somecolumn) VALUES ('somedata');
> INSERTsdf; COMMIT;
>
> I get this reply
> BEGIN
> INSERT 180610 1
> ERROR: syntax error at or near "INSERTsdf" at character 1
> ROLLBACK
>
> Everything seems to be logical and works fine. So why this does not
> work from PHP? I figured one thing to workaround my problem: I am
> sending the query like this:
> BEGIN;
> (here are few insert queries, one is syntax error);
> COMMIT;
> Then I check the pg_result of this query in PHP, and if it is FALSE I
> have to send another simple query : "COMMIT;" - yes I know this is
> second commit already. But it works this way!
> It seems like if PHP ignored my COMMIT command from the transaction query.
> I also tried sending the transaction query like this:
> BEGIN;
> some queries;
> COMMIT;COMMIT;
> but this is not working. I need to send one transaction query, check
> if the result is false, then send another COMMIT.
>
> Any ideas where I got something missed?
>
> Regards,
> Mike
>
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--
Mihail Mihailov, lehtori
Käännöstiede (venäjä)
Kieli- ja käännöstieteiden laitos
33014 Tampereen yliopisto
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sähköposti: mihail(dot)mihailov(at)uta(dot)fi