From: | Amit Langote <Langote_Amit_f8(at)lab(dot)ntt(dot)co(dot)jp> |
---|---|
To: | Michael Paquier <michael(at)paquier(dot)xyz>, Alvaro Herrera <alvherre(at)2ndquadrant(dot)com> |
Cc: | pgsql-committers(at)lists(dot)postgresql(dot)org |
Subject: | Re: [Suspect SPAM] Re: pgsql: Add pg_partition_root to display top-most parent of a partition |
Date: | 2019-03-22 04:09:23 |
Message-ID: | 06be11a6-fd8d-b68b-1b97-1bafb1d3185c@lab.ntt.co.jp |
Views: | Raw Message | Whole Thread | Download mbox | Resend email |
Thread: | |
Lists: | pgsql-committers |
Hi,
On 2019/03/22 12:55, Michael Paquier wrote:
> On Fri, Mar 22, 2019 at 12:26:12AM -0300, Alvaro Herrera wrote:
>> I noticed days ago that if you call pg_partition_root on the topmost
>> partitioned table, the server crashes :-)
I thought we already fixed that last month, but that was pg_partition_tree().
> It's when you think that the thing is actually done that another issue
> pops up. The attached fixes the issue, I suggest to return the
> top-most parent as result if the input is the top-most parent itself.
> Returning NULL does not make sense as in this case the relation can be
> part of a partition tree.
Thanks for writing the patch.
/* Fetch the top-most parent */
ancestors = get_partition_ancestors(relid);
Maybe, the patch should update this comment to say "Fetch the list of
ancestors".
+
+ /*
+ * If the listed partition is already the top-most parent, just
+ * return itself.
+ */
What does "listed partition" mean? Maybe, you mean "If the input
relation..."? How about write this as:
If the input relation is itself the top-most parent, just return itself.
Regards,
Amit
From | Date | Subject | |
---|---|---|---|
Next Message | Michael Paquier | 2019-03-22 04:12:25 | Re: [Suspect SPAM] Re: pgsql: Add pg_partition_root to display top-most parent of a partition |
Previous Message | Michael Paquier | 2019-03-22 03:55:38 | Re: pgsql: Add pg_partition_root to display top-most parent of a partition |