| From: | Andres Freund <andres(at)anarazel(dot)de> |
|---|---|
| To: | Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> |
| Cc: | Nazir Bilal Yavuz <byavuz81(at)gmail(dot)com>, Peter Eisentraut <peter(at)eisentraut(dot)org>, Bertrand Drouvot <bertranddrouvot(dot)pg(at)gmail(dot)com>, pgsql-hackers(at)lists(dot)postgresql(dot)org |
| Subject: | Re: Enable -Wstrict-prototypes and -Wold-style-definition by default |
| Date: | 2026-03-18 17:26:26 |
| Message-ID: | pvwv3lp7te6nxbmb2mr6oiyxcwf5fq4vjbbtf5s2yu6bpyqn6z@k3gc2bjmlcbu |
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| Lists: | pgsql-hackers |
Hi,
On 2026-03-18 13:03:03 -0400, Tom Lane wrote:
> Nazir Bilal Yavuz <byavuz81(at)gmail(dot)com> writes:
> > I got this warning while running headerscheck after this commit:
>
> > ~/Desktop/projects/postgres/src/interfaces/ecpg/ecpglib/ecpglib_extern.h:221:40:
> > warning: function declaration isn’t a prototype [-Wstrict-prototypes]
> > 221 | void ecpg_init_sqlca(struct sqlca_t *sqlca)
>
> Yeah, I see that too. I believe the problem is that headerscheck
> doesn't cause POSTGRES_ECPG_INTERNAL to become defined, so that
> what the compiler is seeing is (from sqlca.h):
>
> #ifndef POSTGRES_ECPG_INTERNAL
> #define sqlca (*ECPGget_sqlca())
> #endif
>
> and then
>
> void ecpg_init_sqlca(struct sqlca_t *sqlca);
>
> Kinda surprising that that's not a syntax error.
Indeed.
I don't even really understand what that POSTGRES_ECPG_INTERNAL business is
about. Is that really just so we can use a local "sqlca" variable in some of
our own ecpglib code while code using ecpg can't do that? Please tell me it
ain't so.
> We could plausibly fix this either by
>
> (1) renaming ecpg_init_sqlca's parameter to something else;
>
> (2) ensuring that POSTGRES_ECPG_INTERNAL is defined. I'd be inclined
> to make ecpglib_extern.h do that rather than expecting headerscheck
> to know about it.
> Neither of these options are beautiful, but perhaps #1 is slightly
> less ugly. Any preferences?
1) seems to be the preferrable approach. It's what code using ecpg already has
to do, right?
Greetings,
Andres Freund
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