Re: Compare the resulta of a count sql into bash

On 2011-01-26, manuel antonio ochoa <manuel8aalfaro(at)gmail(dot)com> wrote:
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> Hello,
> I have the next :
>
> COUNTONE=`/var/lib/pgsql/bin/./psql -U 'Thor' -d princlocal -p 5432 -h
> 192.170.1.82 -c "select count(*) from monterrey.${NOMBRETB}"`
> COUNTTWO=`/var/lib/pgsql/bin/./psql -U 'Thor' -dprinclocal -p 5432 -h
> 192.170.1.82 -c "select count(*) from monterrey.$nombre where recibo
> between '$FI' and '$FF'"
>
> I want to compare the result countone with countwo how does it works ?

you need -t

COUNTONE=`/var/lib/pgsql/bin/./psql -t -U 'Thor' -d princlocal -p 5432 -h 192.170.1.82 -c "select count(*) from monterrey.${NOMBRETB}"`
COUNTTWO=`/var/lib/pgsql/bin/./psql -t -U 'Thor' -d princlocal -p 5432 -h 192.170.1.82 -c "select count(*) from monterrey.$nombre where recibo between '$FI' and '$FF'"`

or like this:

CONN="user=Thor database=princlocal port=5432 host=192.170.1.82"
PSQL=/var/lib/pgsql/bin/psql
COUNTONE=`$PSQL "$CONN" -t -c "select count(*) from monterrey.${NOMBRETB}"`
COUNTTWO=`$PSQL "$CONN" -t -c "select count(*) from monterrey.$nombre where recibo between '$FI' and '$FF'"`

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