Ordering a date_part() query ...

I have a query that looks like:

SELECT ( date_part('month', stat_period) || '/' ||
date_part('day', stat_period) || '/' ||
date_part('year', stat_period) || ' ' ||
date_part('hour', stat_period) || ':00:00' ) as "Summary - by
Day/Hour",
sum(impressions) as impressions, sum(click_thru) as click_thru
FROM banner_count
GROUP BY "Summary - by Day/Hour";

Works great, except that the output looks like:

Summary - by Day/Hour|impressions|click_thru
---------------------+-----------+----------
1/17/2000 23:00:00 | 63| 1
1/18/2000 0:00:00 | 151| 0
1/18/2000 10:00:00 | 348| 4
1/18/2000 11:00:00 | 804| 1
1/18/2000 12:00:00 | 180| 1
1/18/2000 1:00:00 | 89| 0
1/18/2000 2:00:00 | 112| 0
1/18/2000 3:00:00 | 178| 0
1/18/2000 4:00:00 | 184| 0
1/18/2000 5:00:00 | 133| 0
1/18/2000 6:00:00 | 119| 0
1/18/2000 7:00:00 | 148| 0
1/18/2000 8:00:00 | 224| 0
1/18/2000 9:00:00 | 272| 0

Notice the 10/11/12/etc hour stats come before the 1am stats?

So its sorting okay on the date, but I need to get it to d it on the time
as well..

I'm still playing with it, but if someone can suggest a means of doing
this, I'm all ears :)

Thanks...

Marc G. Fournier ICQ#7615664 IRC Nick: Scrappy
Systems Administrator @ hub.org
primary: scrappy(at)hub(dot)org secondary: scrappy(at){freebsd|postgresql}.org