RE: [PHP3] [OFF-TOPIC] POSTGRES

CC'd to the PostgreSQL Hackers list.

I performed the same test as Brian on the cvs version of 6.4 and it
exhibits the same behavior. could we get a fix in for the release.
-DEJ

> Hehehe...
>
> Try using the "*", as I posted to your early send... see if it makes
> any
> difference.
Doing a like '*' will search for the character '*';

> > er sorry about that last "early send" message...
> >
> > well, at first I though you were correct, but it turns out that
> > postgresql
> > is also inconsistent. Consider a table with a field username. 3
> records:
> >
> > "Brian % Schaffner"
> > "Brian T Schaffner"
> > "%"
> >
> > select * from table where username='%' gets all rows (expected)
> > select * from table where username='%%' gets the row with "%"
> (expected)
> > select * from table where username='%%%' gets the row with "%"
> > (expected)
> > select * from table where username='%%%%' gets no rows (expected)
> > select * from table where username='% %' gets the 2 name rows
> (expected)
> > select * from table where username='% %%' gets the 2 name rows (NOT
> > expected)
> > select * from table where username='%% %' gets no rows (NOT
> expected)
> > select * from table where username='% % %' gets the 2 name rows
> > (expected)
> > select * from table where username='% %% %' gets the 2 name rows
> (NOT
> > expected)
> > select * from table where username='% % % %' gets no rows (expected)
> >
> > so, if %% is the LIKE representation for a literal %, then why does
> '%
> > %%' return
> > the 2 name rows, and '%% %' return no rows, and '% %% %' not return
> the
> > row with the
> > embedded literal %?
> >
> > I could not get postgres to single out the row with the embedded %
> using
> > LIKE.
> >
> > why is this not getting any easier to define?
> >
> > -----Original Message-----
> > From: Daniel J. Lashua [mailto:djl(at)stftx9(dot)irngtx(dot)tel(dot)gte(dot)com]
> > Sent: Friday, September 25, 1998 10:58 AM
> > To: Brian Schaffner
> > Cc: 'Rasmus Lerdorf'; 'bourbon(at)bourbon(dot)netvision(dot)net(dot)il';
> > php3(at)lists(dot)php(dot)net
> > Subject: RE: [PHP3] ARGH!! strstr() changed?
> >
> >
> > On Fri, 25 Sep 1998, Brian Schaffner wrote:
> >
> > > in PostgreSQL (6.3.2 on FreeBSD 2.2.6):
> > >
> > > select * from table where field like '%%';
> > >
> > > returns NO rows;
> > >
> > > select * from table where field like '%';
> > >
> > > returns ALL rows;
> > >
> > > -brian-
> > >
> >
> >
> > I am not in any way doubting what you say... but that doesn't seem
> > right.
> > They should both reuturn all rows. Maybe in Postgres %% is the way
> to
> > state you actually want to search for ONE "%"?
> >
> > Out of curiosity, if you have time, could you test that. Make a
> table
> > with
> > a field and in one row of the table in the field insert "%". Then do
> > your
> > select * from table where somefield LIKE '%%' and see if it returns
> the
> > one row?
> >
> > Am I offbase, or does that sound like incorrect behavior to you too?
> >
> > Daniel
> >
> >
>
>
> --
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