From: | Alban Hertroys <haramrae(at)gmail(dot)com> |
---|---|
To: | Thorsten Glaser <tg(at)evolvis(dot)org> |
Cc: | Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>, pgsql-general(at)lists(dot)postgresql(dot)org |
Subject: | Re: DISTINCT *and* ORDER BY in aggregate functions on expressions(!)y |
Date: | 2023-02-28 08:10:54 |
Message-ID: | D9BE942C-58B4-48D0-9DA1-2B7514BA4881@gmail.com |
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Lists: | pgsql-general |
> On 28 Feb 2023, at 3:54, Thorsten Glaser <tg(at)evolvis(dot)org> wrote:
(…)
>> Well, that may be what you want, but it's not what you wrote in
>> the query. Follow David's advice and do
> […]
>> I'm pretty sure that this will only incur one evaluation of the
>> common subexpression, so even though it's tedious to type it's not
>> inefficient.
>
> Thanks. But I fear it’s not as simple as you wrote. More like:
>
> jsonb_build_object('opening_times',
> jsonb_agg(DISTINCT jsonb_build_object(
> 'weekday', cot.weekday,
> 'from_hour', cot.from_hour,
> 'to_hour', cot.to_hour)
> ORDER BY
> jsonb_build_object(
> 'weekday', cot.weekday,
> 'from_hour', cot.from_hour,
> 'to_hour', cot.to_hour)->>'weekday',
> jsonb_build_object(
> 'weekday', cot.weekday,
> 'from_hour', cot.from_hour,
> 'to_hour', cot.to_hour)->>'from_hour',
> jsonb_build_object(
> 'weekday', cot.weekday,
> 'from_hour', cot.from_hour,
> 'to_hour', cot.to_hour)->>'to_hour')
> )
>
> Isn’t that more like it?
Perhaps you can use a lateral cross join to get the result of jsonb_build_object as a jsonb value to pass around?
Alban Hertroys
--
If you can't see the forest for the trees,
cut the trees and you'll find there is no forest.
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