Regex Replace with 2 conditions

From: Denisa Cirstescu <Denisa(dot)Cirstescu(at)tangoe(dot)com>
To: "pgsql-general(at)postgresql(dot)org" <pgsql-general(at)postgresql(dot)org>
Subject: Regex Replace with 2 conditions
Date: 2018-02-05 13:34:37
Message-ID: CY1PR12MB0025991A94F3519B1CB8796BE6FE0@CY1PR12MB0025.namprd12.prod.outlook.com
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Hi all,

Is there a way to specify 2 conditions in regexp_replace?
I need an SQL function that eliminates all ASCII characters from 1-255 that are not A-Z, a-z, 0-9, and special characters % and _ so something like:

SELECT regexp_replace(p_string, E'[' || CHR(1) || '-' || CHR(255) || '&&[^A-Za-z0-9%_]]', '', 'g'));

But this syntax is not really working.

I have written a SQL function that achieves this, but I am not happy with it because it is hard to read and maintain:

-- Eliminates all ASCII characters from 1-255 that are not A-z, a-z, 0-9, and special characters % and _
-- The computed regex expression that is between E[] is CHR(1)-$&-/:-(at)[-^`{-ÿ](dot)
CREATE OR REPLACE FUNCTION testFunction(p_string CHARACTER VARYING) RETURNS VARCHAR AS $$
SELECT regexp_replace(p_string, E'[' || CHR(1) || '-' || CHR(36) || CHR(38) || '-' || CHR(47) || CHR(58) || '-' || CHR(64) || CHR(91) || '-' || CHR(94) || CHR(96) || CHR(123) || '-' || CHR(255) || ']', '', 'g');
$$ LANGUAGE sql IMMUTABLE;

Please help me figure out how to achieve this.

Thanks a lot,
Denisa Cîrstescu

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