From: | David Rowley <david(dot)rowley(at)2ndquadrant(dot)com> |
---|---|
To: | Alvaro Herrera <alvherre(at)alvh(dot)no-ip(dot)org> |
Cc: | Simon Riggs <simon(at)2ndquadrant(dot)com>, Robert Haas <robertmhaas(at)gmail(dot)com>, Pg Hackers <pgsql-hackers(at)postgresql(dot)org>, Maksim Milyutin <milyutinma(at)gmail(dot)com> |
Subject: | Re: [HACKERS] Proposal: Local indexes for partitioned table |
Date: | 2017-11-17 11:58:04 |
Message-ID: | CAKJS1f_WMiAnHKDNDQ_gMBGSqJkVW5GNRUX4SG18m-r9RF0-gQ@mail.gmail.com |
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Lists: | pgsql-hackers |
On 15 November 2017 at 06:49, Alvaro Herrera <alvherre(at)alvh(dot)no-ip(dot)org>
wrote:
> Here's the remaining bits, rebased.
Hi,
I've not had time for a thorough look at this, but on a quick scan I
noticed that CompareIndexInfo() missed checking if the Index AM matches the
AM of the partitioned index.
Testing with:
create table p (a int not null) partition by range (a);
create table p1 partition of p for values from (1) to (10);
create table p2 partition of p for values from (10) to (20);
create index on p1 using btree (a);
create index on p2 using hash (a);
create index on p (a);
I see it ends up making use of the hash index on p2 to support the index
that's stored as a btree on the partitioned table. I think these should
match so that the operations we can perform on the index are all aligned.
--
David Rowley http://www.2ndQuadrant.com/
PostgreSQL Development, 24x7 Support, Training & Services
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