From: | Shreeyansh Dba <shreeyansh2014(at)gmail(dot)com> |
---|---|
To: | Olivier Leprêtre <o(dot)lepretre(at)gmail(dot)com> |
Cc: | pgsql-admin <pgsql-admin(at)postgresql(dot)org> |
Subject: | Re: filter partitions |
Date: | 2018-02-15 10:58:52 |
Message-ID: | CAGDYbUMzGgrjkuS62t21GkJGxwwCK21gogniYiDNWdHOFBHJ5w@mail.gmail.com |
Views: | Raw Message | Whole Thread | Download mbox | Resend email |
Thread: | |
Lists: | pgsql-admin |
Hi Oliver,
You can use the below query to get output for filtering table partition 2,4.
select p,item from parent_table where item='D' and p in (2,4) group by
p,item;
Hope this helps.
On Tue, Feb 13, 2018 at 8:37 PM, Olivier Leprêtre <o(dot)lepretre(at)gmail(dot)com>
wrote:
> Hi,
>
>
>
> I wonder how could it be possible to extract partitions that contains a
> peculiar item
>
>
>
> Consider 4 partitions 1, 2, 3, 4 with different items A, B, C... inside
>
>
>
> P item
>
> 1 A
>
> 1 B
>
> 1 C
>
> 2 B
>
> *2 D*
>
> 2 G
>
> 2 H
>
> 3 B
>
> 3 C
>
> 4 X
>
> *4 D*
>
> 4 Z
>
>
>
>
>
> How could a select return partitions 2,4 because they both contains D item
> ?
>
>
>
> As a result, I would get :
>
>
>
> 2 B
>
> 2 D
>
> 2 G
>
> 2 H
>
> 4 X
>
> 4 D
>
> 4 Z
>
>
>
> I can filter partitions with lag, lead, nth_value... but how could I write
> something like "select P,any (item=D) over (partition by P) from..."
>
>
>
> Thanks for any help,
>
>
>
>
>
>
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