| From: | Michael Shapiro <mshapiro51(at)gmail(dot)com> |
|---|---|
| To: | Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> |
| Cc: | pgsql-general(at)lists(dot)postgresql(dot)org |
| Subject: | Re: select view definition from pg_views feature request |
| Date: | 2019-11-05 14:43:51 |
| Message-ID: | CAGCvxeYArO8-tmFD1MzMP8nuAef25fhphPA6K38k6hV5jpoNEg@mail.gmail.com |
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| Thread: | |
| Lists: | pgsql-general |
Can I set search_path='' (ie to a string that does not match any existing
schema)? Would that be the proper way to guarantee that the definition for
any view will always be fully-qualified?
On Sun, Nov 3, 2019 at 3:15 PM Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> wrote:
> Michael Shapiro <mshapiro51(at)gmail(dot)com> writes:
> > It seems that the definition of a view from pg_catalog.pg_views does not
> > qualify the tables used in the view if the tables are in the current
> search
> > path.
>
> > Is it possible to either have the definition always qualify all tables
> > independent of the search_path (or else provide a new column that does
> > that)?
>
> Why don't you just change the search path to empty before selecting?
>
> regards, tom lane
>
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