From: | Pavel Stehule <pavel(dot)stehule(at)gmail(dot)com> |
---|---|
To: | Ramesh T <rameshparnanditech(at)gmail(dot)com> |
Cc: | Adrian Klaver <adrian(dot)klaver(at)aklaver(dot)com>, "pgsql-general(at)postgresql(dot)org" <pgsql-general(at)postgresql(dot)org> |
Subject: | Re: xml |
Date: | 2015-03-23 12:30:44 |
Message-ID: | CAFj8pRA8zVpoLtwVe2SaOEOnbOhbRTXCqN70GKjfMHmc3htpaA@mail.gmail.com |
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Lists: | pgsql-general |
2015-03-23 12:40 GMT+01:00 Ramesh T <rameshparnanditech(at)gmail(dot)com>:
> Hi all,
> SELECT xmlagg(xmlelement(
> name actor, xmlattributes(first_name)
> )ORDER BY actor_id,',')from actor;
>
> the above code return following result,
>
> [image: Inline image 1]
> Question :
>
> i want retrieve result from above XML result like
> penelope,nick,jennifer,jhony,,,,,
>
>
result of xmlagg is not valid xml.
if you use xmlelement, then you can get valid xml
ostgres=# select * from x;
a
---------------------------------------------------------------
<d><actor first_name="Pavel"/><actor first_name="Tomas"/></d>
(1 row)
postgres=# select unnest(xpath('//actor/@first_name',a)::text[]) from x;
unnest
--------
Pavel
Tomas
(2 rows)
Regards
Pavel
>
> xpath is their but unable to fix this query.
>
> any help how to get only names from query not xml.
>
>
>
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