From: | Dilip Kumar <dilipbalaut(at)gmail(dot)com> |
---|---|
To: | Fabien COELHO <coelho(at)cri(dot)ensmp(dot)fr> |
Cc: | Amit Langote <amitlangote09(at)gmail(dot)com>, Amit Kapila <amit(dot)kapila16(at)gmail(dot)com>, Asif Rehman <asifr(dot)rehman(at)gmail(dot)com>, PostgreSQL Developers <pgsql-hackers(at)lists(dot)postgresql(dot)org> |
Subject: | Re: pgbench - allow to create partitioned tables |
Date: | 2019-09-18 10:47:45 |
Message-ID: | CAFiTN-u3n1o1Pu3hwJfK0ZTm-0_4OeQQ0QQbNUEE5chA46kVNQ@mail.gmail.com |
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On Wed, Sep 18, 2019 at 1:02 PM Fabien COELHO <coelho(at)cri(dot)ensmp(dot)fr> wrote:
>
*/
+ res = PQexec(con,
+ "select o.n, p.partstrat, pg_catalog.count(p.partrelid) "
+ "from pg_catalog.pg_class as c "
+ "join pg_catalog.pg_namespace as n on (n.oid = c.relnamespace) "
+ "cross join lateral (select
pg_catalog.array_position(pg_catalog.current_schemas(true),
n.nspname)) as o(n) "
+ "left join pg_catalog.pg_partitioned_table as p on (p.partrelid = c.oid) "
+ "left join pg_catalog.pg_inherits as i on (c.oid = i.inhparent) "
+ /* right name and schema in search_path */
+ "where c.relname = 'pgbench_accounts' and o.n is not null "
+ "group by 1, 2 "
+ "order by 1 asc "
I have a question, wouldn't it be sufficient to just group by 1? Are
you expecting multiple pgbench_account tables partitioned by different
strategy under the same schema?
--
Regards,
Dilip Kumar
EnterpriseDB: http://www.enterprisedb.com
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