| From: | Juan José Santamaría Flecha <juanjo(dot)santamaria(at)gmail(dot)com> |
|---|---|
| To: | Michael Paquier <michael(at)paquier(dot)xyz> |
| Cc: | Sandeep Thakkar <sandeep(dot)thakkar(at)enterprisedb(dot)com>, serpashk(at)gmail(dot)com, pgsql-bugs(at)lists(dot)postgresql(dot)org |
| Subject: | Re: BUG #15789: libpq compilation with OpenSSL 1.1.1b fails on Windows with Visual Studio 2017 |
| Date: | 2019-06-05 07:29:21 |
| Message-ID: | CAC+AXB3_YNqAr=u9ccuXOoKQF=kZRQFjnLgRaSFQEjNz+Po+1w@mail.gmail.com |
| Views: | Raw Message | Whole Thread | Download mbox | Resend email |
| Thread: | |
| Lists: | pgsql-bugs |
On Tue, Jun 4, 2019 at 1:51 AM Michael Paquier <michael(at)paquier(dot)xyz> wrote:
> On Mon, Jun 03, 2019 at 03:30:49PM +0530, Sandeep Thakkar wrote:
> > OpenSSL 1.1.0 and 1.0.2 both are going out of Support in 2019 and PG 9.4
> is
> > supported till Feb2020.
> > Ideally, 1.1.1x support should be backpatched until 9.4
>
> There is no point to patch a stable branch if it has no support for
> the OpenSSL version we target. Now, bb132cdd has added support for
> OpenSSL 1.1.0 in 9.4, so there is actually no reason to not patch 9.4
> as well and you are right.
>
The patches are intended to support OpenSSL 1.1.x, including 1.1.1x.
The attached patches are meant for all supported versions and HEAD.
Regards,
Juan José Santamaría Flecha
| Attachment | Content-Type | Size |
|---|---|---|
| 0001_windows_openssl_1.1.0_build_PG10_v1.patch | application/octet-stream | 4.2 KB |
| 0001_windows_openssl_1.1.0_build_PG11_&_HEAD_v1.patch | application/octet-stream | 4.2 KB |
| 0001_windows_openssl_1.1.0_build_PG94_v1.patch | application/octet-stream | 4.2 KB |
| 0001_windows_openssl_1.1.0_build_PG95_&_PG96_v1.patch | application/octet-stream | 4.3 KB |
| From | Date | Subject | |
|---|---|---|---|
| Next Message | PG Bug reporting form | 2019-06-05 10:50:35 | BUG #15833: defining a comment on a domain constraint fails with wrong OID |
| Previous Message | Ashutosh Sharma | 2019-06-05 06:57:14 | Re: BUG #15832: COPY into a partitioned table breaks its indexes |