Re: Can Postgres beat Oracle for regexp_count?

From: Shaozhong SHI <shishaozhong(at)gmail(dot)com>
To: Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>
Cc: "David G(dot) Johnston" <david(dot)g(dot)johnston(at)gmail(dot)com>, pgsql-general <pgsql-general(at)lists(dot)postgresql(dot)org>
Subject: Re: Can Postgres beat Oracle for regexp_count?
Date: 2022-02-03 05:26:14
Message-ID: CA+i5JwZxxVy0uwg9bKYQOs=PZ617Xr7xTaPm4eqsrzsBz-BxNw@mail.gmail.com
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Hi, Tom, Lane,

On Wed, 2 Feb 2022 at 22:26, Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> wrote:

> "David G. Johnston" <david(dot)g(dot)johnston(at)gmail(dot)com> writes:
> > Given we don't have a regexp_count function this isn't surprising...
>
> FYI, it's there in HEAD.
>
> In the meantime, you could possibly do something like
>
> =# select count(*) from regexp_matches('My High Street',
> '([A-Z][a-z]+[\s])', 'g');
> count
> -------
> 2
> (1 row)
>
> (Note that 2 is the correct answer given that there's no space
> after the third word; I trust Oracle agrees.)
>
> Can the whole 3 or 4 or 5 to be matched as 1?
>

The following has been attempted but no luck.

select regexp_matches('My High Street', '([A-Z][a-z]+[\s]*)+', 'g')
It is intended to match 'My High Street, but it turned out only 'Street'
was matched.

Regards, David

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