Re: WIP: RangeTypes

On 29 January 2011 19:53, Jeff Davis <pgsql(at)j-davis(dot)com> wrote:
> On Sat, 2011-01-29 at 14:42 -0500, Tom Lane wrote:
>> Jeff Davis <pgsql(at)j-davis(dot)com> writes:
>> > On Fri, 2011-01-28 at 21:52 +0000, Thom Brown wrote:
>> > Also, if I try the same, but with a different name for the type, I get
>> > the same error.  Why does that restriction exist?  Can't you have
>> > types which happen to use the exact same subtype?
>>
>> > At first, that's how I designed it. Then, I realized that the type
>> > system needs to know the range type from the element type in order for
>> > something like ANYRANGE to work.
>>
>> That seems like a fairly bad restriction.  In a datatype with multiple
>> useful sort orderings, it'd be desirable to be able to create a range
>> type for each such ordering, no?  I'd be inclined to think of a range
>> type as being defined by element type plus a btree opfamily.  Maybe it'd
>> be okay to insist on that combination as being unique.
>
> I couldn't find another way to make a function with a definition like:
>
>  range(ANYELEMENT, ANYELEMENT) returns ANYRANGE
>
> work. And it seemed worse to live without a constructor like that.
> Ideas?
>
> Also, it's not based on the btree opfamily right now. It's just based on
> a user-supplied compare function. I think I could change it to store the
> opfamily instead, if you think that's a better idea.

Probably ignorance here, but why does the following not work?

postgres=# select '[18,20]'::numrange @> 19;
ERROR: operator does not exist: numrange @> integer
LINE 1: select '[18,20]'::numrange @> 19;
^
HINT: No operator matches the given name and argument type(s). You
might need to add explicit type casts.

I can see both the wiki page on range types and the pg_operator table
appear to indicate this should work:

postgres=# select o.oprname, tl.typname as lefttype, tr.typname as
righttype from pg_operator o left join pg_type tl on o.oprleft =
tl.oid left join pg_type tr on o.oprright = tr.oid where 'anyrange' in
(tl.typname, tr.typname) and oprname = '@>';
oprname | lefttype | righttype
---------+----------+-------------
@> | anyrange | anynonarray
@> | anyrange | anyrange
(2 rows)

--
Thom Brown
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