Re: 7.4 aggregate OR TRUE yields strange results

From: Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>
To: SZŰCS Gábor <surrano(at)mailbox(dot)hu>
Cc: pgsql-bugs(at)postgresql(dot)org, TIR(at)yahoogroups(dot)com
Subject: Re: 7.4 aggregate OR TRUE yields strange results
Date: 2004-02-13 22:28:43
Message-ID: 6044.1076711323@sss.pgh.pa.us
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"=?iso-8859-2?B?U1rbQ1MgR+Fib3I=?=" <surrano(at)mailbox(dot)hu> writes:
> SELECT count(*)<0 OR TRUE FROM mytable WHERE condition
> dumps the whole tuples meeting the condition.

Sigh, I'm an idiot. I introduced this bug more than a year ago.
(Bit surprising that it wasn't caught already...) Patch against 7.4.*
is attached.

regards, tom lane

Index: planner.c
===================================================================
RCS file: /cvsroot/pgsql-server/src/backend/optimizer/plan/planner.c,v
retrieving revision 1.161
diff -c -r1.161 planner.c
*** planner.c 25 Sep 2003 06:58:00 -0000 1.161
--- planner.c 13 Feb 2004 22:22:26 -0000
***************
*** 701,719 ****

/*
* Will need actual number of aggregates for estimating costs.
- * Also, it's possible that optimization has eliminated all
- * aggregates, and we may as well check for that here.
*
* Note: we do not attempt to detect duplicate aggregates here; a
* somewhat-overestimated count is okay for our present purposes.
*/
if (parse->hasAggs)
- {
numAggs = count_agg_clause((Node *) tlist) +
count_agg_clause(parse->havingQual);
- if (numAggs == 0)
- parse->hasAggs = false;
- }

/*
* Figure out whether we need a sorted result from query_planner.
--- 701,718 ----

/*
* Will need actual number of aggregates for estimating costs.
*
* Note: we do not attempt to detect duplicate aggregates here; a
* somewhat-overestimated count is okay for our present purposes.
+ *
+ * Note: think not that we can turn off hasAggs if we find no aggs.
+ * It is possible for constant-expression simplification to remove
+ * all explicit references to aggs, but we still have to follow the
+ * aggregate semantics (eg, producing only one output row).
*/
if (parse->hasAggs)
numAggs = count_agg_clause((Node *) tlist) +
count_agg_clause(parse->havingQual);

/*
* Figure out whether we need a sorted result from query_planner.

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