How many table scans in a delete...

I am just trying to understand how Postgres does its delete work.

If I have a table testDad with a primary key on cola and no index on colb, and I have a kid table testKid with a foreign key to reference testDad but no index created on the foreign key column on table testKid.

I have 10,000 rows in each table and I want to delete 5000 rows from the Dad table, of course , I have to kill all the kids in the Kid table first so that I won't get the constraint error.

Now I am ready to run my delete command on the Dad table with the following command:

delete from testDad where colb = 'abc';

(supposed select count(*) from testDad where colb = 'abc' will give me 5000 rows)

Since I don't have any index on testDad.colb, I know it is going to do a table scan on the table testDad to find all the qualified rows for the delete.

My question1: how many table scans will this single transaction do to find all 5000 qualified rows on the Dad table testDad? Does it scan the entire table once to get all qualified deletes? or it has to do the table scan 5000 times on testDad?

then, after all the 5000 qualified rows have been found on table testDad, the constraints between the Dad and Kid table will be checked against those 5000 qualified rows on table testDad.

My question 2: does it take one qualified row at a time from the Dad table then do a table scan on the kid table for constraint check? In this case, it will have to do 5000 times of table scan on the kid table. very unlikely it will scan the kid table only once to do all constraint checking for 5000 different primary values...

Thanks,
Jessica