Re: partition text/varchar check problem

Ireneusz Pluta wrote:
> Can you show what you get from:
> EXPLAIN SELECT * FROM data WHERE name LIKE 'a%'
>
> ?
>
> Irek.

I get:
QUERY PLAN
------------------------------------------------------------------------
Result (cost=0.00..24.42 rows=8 width=48)
-> Append (cost=0.00..24.42 rows=8 width=48)
-> Seq Scan on data (cost=0.00..22.38 rows=5 width=48)
Filter: ((name)::text ~~ 'a%'::text)
-> Seq Scan on data_a data (cost=0.00..1.02 rows=2 width=23)
Filter: ((name)::text ~~ 'a%'::text)
-> Seq Scan on data_b data (cost=0.00..1.02 rows=1 width=23)
Filter: ((name)::text ~~ 'a%'::text)
(8 rows)

Both partition tables are scanned.

Best,
jamcito

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