Re: [HACKERS] 8.2 features?

Tom Lane wrote:
> Joe Conway <mail(at)joeconway(dot)com> writes:
>
>>I wanted to post an updated patch even though there are still things not
>>working again after conversion to bare expressions.
>
> I've been through the planner part of this and it looks OK (one or two
> small errors). I'm currently messing with a revised version of the
> grammar that supports putting VALUES everyplace that the spec allows,
> and is a bit simpler than the old one to boot: it folds VALUES and
> SELECT together, so we need fewer cases in the INSERT production.
> Of course this breaks most of what you did in the parser :-( ...
> I'm working on fixing that.
>
> I'm about to go out to dinner but thought I'd post the gram.y and
> parsenodes.h files so you could see where I'm headed. These are
> diffs from CVS tip, not from your patch.
>

Yup, I can see where you're headed. Looks nice!

In case you can make use of it, here's my latest. I found that I was
being too aggressive at freeing the input nodes to transformExpr() in
transformRangeValues() after using them. In many cases the returned node
is a new palloc'd node, but in some cases it is not.

The other issue I found was that I had neglected to fixup/coerce the raw
expressions ala updateTargetListEntry(). I ended up creating a somewhat
simpler updateValuesExprListEntry() to use on values expression lists.

I have yet to get to the similar/more general issue of coercing values
expression lists to common datatypes (i.e. using select_common_type()).

FWIW, here's a list of non-working cases at the moment:

8<-------------------------------------
create table inserttest (col1 int4, col2 int4 NOT NULL, col3 text
default 'testing');

--doesn't work
---------------
--wrong result
insert into inserttest (col2, col3) values (23, DEFAULT), (24, DEFAULT),
(25, 'hello'), (26, DEFAULT);
select * from (values (3,4),(2,3)) as t1(f1,f2) join (values
(3,8),(2,6)) as t2(f1,f2) using (f1);
select * from (values (3,4),(2,3)) as t1(f1,f2) join (values
(3,8),(2,6)) as t2(f1,f2) using (f1) where t2.f2 = 8;
select * from (values (3,4),(2,3)) as t1(f1,f2) join (values
(3,8),(2,6)) as t2(f1,f2) on t1.f1 = t2.f2 where t1.f1 = 3;

--corrupt result but no crash
select f1,f2 from (values (11,2),(26,'a'),(6,4)) as t(f1,f2) order by 1
desc;

--crash
select f1 from (values (1,2),(2,3)) as t(f1,f2) order by 1 desc;
select f1,f2 from (values (11,'a'),(26,13),(6,'c')) as t(f1,f2) order by
1 desc;
8<-------------------------------------

Joe