| From: | Adrian Klaver <adrian(dot)klaver(at)aklaver(dot)com> |
|---|---|
| To: | "David G(dot) Johnston" <david(dot)g(dot)johnston(at)gmail(dot)com> |
| Cc: | Divyansh Gupta JNsThMAudy <ag1567827(at)gmail(dot)com>, pgsql-general(at)lists(dot)postgresql(dot)org |
| Subject: | Re: Need help in database design |
| Date: | 2024-12-23 16:59:11 |
| Message-ID: | 43981031-ac2a-4216-9342-8b898a06d0d7@aklaver.com |
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| Lists: | pgsql-general |
On 12/23/24 08:55, David G. Johnston wrote:
> On Mon, Dec 23, 2024, 09:54 Adrian Klaver <adrian(dot)klaver(at)aklaver(dot)com
> <mailto:adrian(dot)klaver(at)aklaver(dot)com>> wrote:
>
> On 12/23/24 08:46, Divyansh Gupta JNsThMAudy wrote:
> > Also as you ask how 50 pairs turns into 50 column so each column
> will be
> > a key and the value of that key will store inside their respective
> > column for each row
>
> My problem with understanding this is 50 pairs = 100 values, I don't
> understand how that can fit in 50 columns that can only handle 1 value
> each. You need to provide some example data showing what you want to
> achieve. It does not need to be the full 50, just something to show the
> process.
>
>
>
> Because the column name is the same as a dictionary key...
Aah, got it thanks.
>
> David J.
>
>
--
Adrian Klaver
adrian(dot)klaver(at)aklaver(dot)com
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