Re: Order by YYYY MM DD in reverse chrono order trouble

From: Edmund Bacon <ebacon(at)onesystem(dot)com>
To: pgsql-sql(at)postgresql(dot)org
Cc: ogjunk-pgjedan(at)yahoo(dot)com
Subject: Re: Order by YYYY MM DD in reverse chrono order trouble
Date: 2004-04-21 14:52:20
Message-ID: 40868AA4.2070501@onesystem.com
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Is there some reason you can't do this:

SELECT DISTINCT
date_part('year', uu.add_date), date_part('month', uu.add_date),
date_part('day', uu.add_date)

FROM uus INNER JOIN ui ON uus.user_id=ui.id INNER JOIN uu ON
ui.id=uu.user_id
WHERE uus.x_id=1

ORDER BY
uu.add_date DESC;

This might be faster, as you only have to sort on one field, and I think it should give the desired results

ogjunk-pgjedan(at)yahoo(dot)com wrote:

>Hello,
>
>I am trying to select distinct dates and order them in the reverse
>chronological order. Although the column type is TIMESTAMP, in this
>case I want only YYYY, MM, and DD back.
>
>I am using the following query, but it's not returning dates back in
>the reverse chronological order:
>
>SELECT DISTINCT
> date_part('year', uu.add_date), date_part('month', uu.add_date),
> date_part('day', uu.add_date)
>
>FROM uus INNER JOIN ui ON uus.user_id=ui.id INNER JOIN uu ON
>ui.id=uu.user_id
>WHERE uus.x_id=1
>
>ORDER BY
>date_part('year', uu.add_date), date_part('month', uu.add_date),
>date_part('day', uu.add_date) DESC;
>
>
>This is what the above query returns:
>
> date_part | date_part | date_part
>-----------+-----------+-----------
> 2004 | 2 | 6
> 2004 | 4 | 20
>(2 rows)
>
>
>I am trying to get back something like this:
>2004 4 20
>2004 4 19
>2004 2 6
>...
>
>My query is obviously wrong, but I can't see the mistake. I was
>wondering if anyone else can see it. Just changing DESC to ASC, did
>not work.
>
>Thank you!
>Otis
>
>
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--
Edmund Bacon <ebacon(at)onesystem(dot)com>

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