Re: sum an alias

In response to Wes James :
> In the statement:
>
> select
> MAX(page_count_count) - MIN(page_count_count) as day_tot,
> MAX(page_count_count) as day_max, sum(MAX(page_count_count) -
> MIN(page_count_count)) as tot,
> page_count_pdate
> from page_count
> group by page_count_pdate order by page_count_pdate
>
> Is there a way to do sum(day_tot) also in the same statement?

Is this the correct table-definition?

test=# \d page_count
Table "public.page_count"
Column | Type | Modifiers
------------------+---------+-----------
page_count_pdate | date |
page_count_count | integer |

If yes, your SQL is wrong:

test=# select
MAX(page_count_count) - MIN(page_count_count) as day_tot,
MAX(page_count_count) as day_max, sum(MAX(page_count_count) -
MIN(page_count_count)) as tot,
page_count_pdate
from page_count
group by page_count_pdate order by page_count_pdate;
ERROR: aggregate function calls cannot be nested
LINE 3: MAX(page_count_count) as day_max, sum(MAX(page_count_cou...

Can you provide the correct table definition?

Regards, Andreas
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Andreas Kretschmer
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