Re: question with times and intervals

Richard Huxton <dev(at)archonet(dot)com> schrieb:

> Now (upper_time - lower_time) is the interval you want and summing them
> will give you your answer.
>
> Any help?

Yes, thanks.

But, i remember a little function that i wrote in the past:
http://a-kretschmer.de/tools/time_intersect.sql

And now i have a solution (i hope):

test=# select id, status,
test-# sum((time_intersect(t_start, t_end, '2006/01/21 00:00:00'::timestamptz, '2006/01/22 23:59:59'::timestamptz)).t2 -
test(# (time_intersect(t_start, t_end, '2006/01/21 00:00:00+1'::timestamptz, '2006/01/22 23:59:59+1'::timestamptz)).t1)
test-# from status_log
test-# where (t_start, t_end) overlaps ('2006/01/21 00:00:00+1'::timestamptz, '2006/01/22 23:59:59'::timestamptz)
test-# group by id, status
test-# order by 1,2;
id | status | sum
----+--------+----------
1 | 1 | 32:00:00
1 | 2 | 15:59:59
(2 rows)

Okay, now i can write a function similar above which returns the
interval and the i can sum() this.

Thanks, Andreas
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