Re: Replace function BUG

7.4.2 gives it like this:

testbed=# select replace('test %%400%% result',
'result', 'ok');
replace
-----------------
test %%400%% ok
(1 row)

testbed =# select replace('test %400% result',
'result', 'ok');
replace
---------------
test %400% ok
(1 row)

Ted

-- Nicolas Bottarini <nicolas(at)avatarla(dot)com> wrote:
> In postgreSQL 7.3.2 when I execute the following
> query
>
> select replace('test %400% result', 'result', 'ok');
>
>
>
> it returns "test % ok"
>
>
>
> And If I Execute:
>
> select replace('test %%400%% result', 'result',
> 'ok');
>
> it returns the correct result: "test %400% ok"
>
>
>
> If this is a known BUG please tell me because I need
> to fix this.
>
>
>
> Thanks
>
>
>
> Nicolas Bottarini
>
>
>
>

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