Re: pg_result

From: Sharmad Naik <sharmad(at)goatelecom(dot)com>
To: ryanne cruz <ryanne(dot)cruz(at)up(dot)edu(dot)ph>
Cc: pgsql-php(at)postgresql(dot)org
Subject: Re: pg_result
Date: 2003-01-24 17:08:34
Message-ID: 20030124223834.377cd8fb.sharmad@goatelecom.com
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Hi,
PLease look at the query.The syntax is

"SELECT attribute_name[,attr2,..] FROM tables WHERE attribute =[LIKE,IN,..] ETC..

It looks in ur query that province is an attribute as well as a query.

Reagrds
Sharmad

On Wed, 22 Jan 2003 14:18:32 +0800
ryanne cruz <ryanne(dot)cruz(at)up(dot)edu(dot)ph> wrote:

>
> hi list.
>
> this is my script:
>
> $query7="select provinceid from province where province like '$tablename1';";
> $result7=pg_exec($conn,$query7);
> if(!$result7){
> .
> .
> .}
> else {
> .
> .
> .
> }
>
> my problem is when the value of the variable $tablename1 is not on the table
> province, it doesn't go to the if statements. what am i doing wrong?
>
> thanks!
>
>
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  • pg_result at 2003-01-22 06:18:32 from ryanne cruz

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