Re: Doing a regexp-based search/replace?

From: Brett Schwarz <brett_schwarz(at)yahoo(dot)com>
To: Steve Frampton <frampton(at)LinuxNinja(dot)com>
Cc: pgsql-sql(at)postgresql(dot)org
Subject: Re: Doing a regexp-based search/replace?
Date: 2001-10-18 18:30:23
Message-ID: 20011018113023.50ac0754.brett_schwarz@yahoo.com
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You could write a Tcl (i.e. pltcl) function, and use that to do what you want:

CREATE FUNCTION remove(varchar) RETURNS varchar AS '

set input $1

regsub -- {-.*$} $input {} output

return $output

' language 'pltcl';

[NOTE: untested]

you may have to monkey with the regexp to get exactly what you want...

--brett

On Thu, 18 Oct 2001 12:03:28 -0400 (EDT)
Steve Frampton <frampton(at)LinuxNinja(dot)com> wrote:

> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
> Hello:
>
> I've got a table containing property_id's with values of the form
> ###-####. I would like to discard the slash onwards (and I can't use a
> substr() because I am not guaranteed if a) the -#### portion exists, b)
> what position it exists from.
>
> If this were a text file, I would use a sed expression such as:
>
> cat textfile | sed 's/-.*$//'
>
> I've been looking for a way to do this with PostgreSQL but so far haven't
> found a function that seems to be suitable. I thought maybe I could do it
> with translate, but translate doesn't appear to work with regular
> expressions. So far I've tried things like:
>
> select translate(property_id, '-.*', '') from mytable;
>
> I need to do this, because the -.* portion of my property_id was entered
> in error, and I would like to do an update on the entire table and just
> have the left-hand side of the property_id column remaining.
>
> Any ideas? Thank you in advance.
>
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> Steve Frampton <frampton(at)LinuxNinja(dot)com> http://www.LinuxNinja.com
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