Re: position('' in '') returns 1 instead of 0

From: Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>
To: terry(at)greatbridge(dot)com, pgsql-bugs(at)postgresql(dot)org
Subject: Re: position('' in '') returns 1 instead of 0
Date: 2001-04-18 21:26:29
Message-ID: 15181.987629189@sss.pgh.pa.us
Views: Raw Message | Whole Thread | Download mbox | Resend email
Thread:
Lists: pgsql-bugs

Terry Carlin (terry(at)greatbridge(dot)com) writes:
> While running an ODBC test suite against PostgreSQL 7.1, the test
> software reported that the ODBC command locate("", "") failed.
> It expected the result to be zero and it got a 1.

Evidently your ODBC test suite hasn't read the spec. See 4.2.2.2 in
either SQL92 or SQL99:

<position expression> determines the first position, if any, at
which one string, S1, occurs within another, S2. If S1 is of length
zero, then it occurs at position 1 for any value of S2. If S1 does
not occur in S2, then zero is returned.

Whether this is useful or not is perhaps debatable, but it's indisputably
what the standard says to do.

regards, tom lane

In response to

Responses

Browse pgsql-bugs by date

  From Date Subject
Next Message Peter Eisentraut 2001-04-18 21:56:57 Re: position('' in '') returns 1 instead of 0
Previous Message Thomas Lockhart 2001-04-18 21:04:58 Re: position('' in '') returns 1 instead of 0