From: | Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> |
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To: | brianb-pgsql(at)edsamail(dot)com |
Cc: | pgsql-sql(at)postgresql(dot)org, Bruce Momjian <pgman(at)candle(dot)pha(dot)pa(dot)us> |
Subject: | Re: Search for underscore w/ LIKE |
Date: | 2000-07-07 17:33:58 |
Message-ID: | 10965.962991238@sss.pgh.pa.us |
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Lists: | pgsql-sql |
brianb-pgsql(at)edsamail(dot)com writes:
> How do I use LIKE to search for strings with an underscore? The
> documentation (well, Bruce's book) says to use 2 underscores (__) but it
> doesn't work.
If Bruce's book says that, I hope it's not too late for him to change
it ;-)
The correct way is to escape the underscore with a backslash. You
actually have to write two backslashes in your query:
select * from foo where bar like '%\\_baz'
The first backslash quotes the second one for the query parser, so that
what ends up inside the system is %\_baz, and then the LIKE function
knows what to do with that.
Similarly, '\\%' would be the way to match a literal %. You can
actually backslash-quote any single character this way in LIKE,
but % and _ are the only ones where it makes a difference. (In the
regexp-matching operators there are many more special characters and
so many more times when you need the backslash trick.)
regards, tom lane
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