From: | "Nikolay Mijaylov" <nmmm(at)nmmm(dot)nu> |
---|---|
To: | "pgsql-general" <pgsql-general(at)postgreSQL(dot)org>, "Tom Lane" <tgl(at)sss(dot)pgh(dot)pa(dot)us> |
Subject: | Re: [SQL] SubSelect as a column |
Date: | 2000-02-08 07:30:27 |
Message-ID: | 003a01bf7206$6031a620$ce2a18c3@skillbrokers.bg |
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Thread: | |
Lists: | pgsql-general pgsql-sql |
Define this as function:
SELECT COUNT(t.techid)
FROM ticket t
WHERE t.techid = $1
Then use this....
SELECT u.idnum, u.username, func(u.idnum)
FROM users u;
--------------------------------------------------------------
The reboots are for hardware upgrades!
"http://www.nmmm.nu; <nmmm(at)nmmm(dot)nu>
----- Original Message -----
From: Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>
To: Lars <lars(at)sscsinc(dot)com>
Cc: <pgsql-sql(at)postgreSQL(dot)org>
Sent: вторник, Февруари 08, 2000 05:33
Subject: Re: [SQL] SubSelect as a column
> Lars <lars(at)sscsinc(dot)com> writes:
> > I am trying to use a subselect as a column name, but it appears as if
this
> > is not supported in Postgresql. Here is the query:
>
> > SELECT u.idnum, u.username,
> > (SELECT COUNT(t.techid)
> > FROM ticket t
> > WHERE t.techid = u.idnum)
> > FROM users u;
>
> Nope, doesn't work in 6.5.*. It is there in current sources for the
> upcoming 7.0 release. Can't think of any good workaround in 6.5...
>
> regards, tom lane
>
> ************
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