From: | Harold A(dot) Giménez Ch(dot) <harold(dot)gimenez(at)gmail(dot)com> |
---|---|
To: | "Karl Denninger" <karl(at)denninger(dot)net> |
Cc: | "chester c young" <chestercyoung(at)yahoo(dot)com>, "sql pgsql" <pgsql-sql(at)postgresql(dot)org> |
Subject: | Re: SQL question.... |
Date: | 2008-05-20 19:54:11 |
Message-ID: | c807ef1a0805201254m26c765fdla975ccbc4eb13d76@mail.gmail.com |
Views: | Raw Message | Whole Thread | Download mbox | Resend email |
Thread: | |
Lists: | pgsql-sql |
I think this is what you're looking for:
SELECT * FROM access
WHERE ip IN(SELECT ip FROM access
GROUP BY ip HAVING count(*) > 1)
On Tue, May 20, 2008 at 3:17 PM, Karl Denninger <karl(at)denninger(dot)net> wrote:
> chester c young wrote:
>
> create table access (name text, address ip)
>
> I want to construct a SELECT statement which will return ONLY tuples
> containing IP and name pairs IF there is an IP that has two or more
> NAMEs associated with it.
>
>
>
>
> many ways:
>
> select a1.* from access a1 where exists(
> select 1 from access a2 where a2.name=a2.name and a1.ip!=a2.ip );
>
> select a1.*
> from access a1
> join access a2 using( name )
> where a1.ip != a2.ip;
>
>
>
> Those will return single entries as well (which is easy to do with an
> "ORDER BY", that is computationally simpler)
>
> What I want (and can't figure out) is a SELECT that returns ONLY tuples
> with two or more NAME entries that have the same IP.
>
> -- Karl
>
From | Date | Subject | |
---|---|---|---|
Next Message | Gurjeet Singh | 2008-05-20 20:57:59 | Re: SQL question.... |
Previous Message | Karl Denninger | 2008-05-20 19:17:34 | Re: SQL question.... |