Re: create table as select... with auto increment id ?

On 07/25/2011 05:17 PM, David Salisbury wrote:
>
> We all know i can
>
> create table freaky as select "abunchofstuff".
>
> I work with rails developers and they are fussy about having an
> auto incrementing "id" field. Is there a way I can eak that out
> of the above type statement, or am I stuck with creating the
> table and no short cuts?
>
> create table freaky ( id autoincrement, and-a-long-list int,
> and-perfect-order float )
> insert into freaky as select "abunchofstuff-in-same-order"
>
> I think I know the answer ;-<

Not exactly as you wanted, but you can do the following:

create table twserid(id serial primary key, f1 text not null);
create table like_twserid(like twserid including all);

contrib_regression=# \d twserid
Table "public.twserid"
Column | Type | Modifiers
--------+---------+------------------------------------------------------
id | integer | not null default nextval('twserid_id_seq'::regclass)
f1 | text | not null
Indexes:
"twserid_pkey" PRIMARY KEY, btree (id)

contrib_regression=# \d like_twserid
Table "public.like_twserid"
Column | Type | Modifiers
--------+---------+------------------------------------------------------
id | integer | not null default nextval('twserid_id_seq'::regclass)
f1 | text | not null
Indexes:
"like_twserid_pkey" PRIMARY KEY, btree (id)

Then something like:
insert into like_twserid select * from twserid;
SELECT setval('twserid_id_seq', (select max(id) from like_twserid));

HTH,

Joe

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Joe Conway
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