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Re: GPL code issue?

From: "Adam H(dot) Pendleton" <fmonkey(at)fmonkey(dot)net>
To: Dave Page <dpage(at)vale-housing(dot)co(dot)uk>
Cc: pgsql-hackers(at)postgresql(dot)org,Andreas Pflug <Andreas(dot)Pflug(at)web(dot)de>, pgadmin-hackers(at)postgresql(dot)org
Subject: Re: GPL code issue?
Date: 2003-10-01 13:53:24
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Lists: pgadmin-hackerspgsql-hackers
Dave Page wrote:

>/* A Bison parser, made by GNU Bison 1.875.  */
Given that this file appears to be produced *by* Bison, and given this 

>/* As a special exception, when this file is copied by Bison into a
>   Bison output file, you may use that output file without restriction.
>   This special exception was added by the Free Software Foundation
>   in version 1.24 of Bison.  */
it would appear that the file can be used without restriction.  Any 
output from bison or flex is non-GPL, AIUI.  Any input *into* bison, 
which is GPL'd before processing, *is* restricted.  Given that bison 
doesn't take .h files as input, doesn't it make sense that this was 
produced *by* bison, and thus unrestricted?


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