Re: Order by YYYY MM DD in reverse chrono order trouble

Hello,

Hm, doesn't work for me:

me(at)[local] mydb=> select distinct date_part('year', uu.add_date),
date_part('month', uu.add_date), date_part('day',
uu.add_date) from uus inner join ui on uus.user_id=ui.id inner join
uu on ui.id=uu.user_id where uus.subscriber_user_id=1 order by
uu.add_date desc;

ERROR: For SELECT DISTINCT, ORDER BY expressions must appear in target
list

I have this version of PostgreSQL installed: postgresql-7.3.4-3.rhl9

Thanks,
Otis

--- Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> wrote:
> <ogjunk-pgjedan(at)yahoo(dot)com> writes:
> > I'd love to be able to do that, but I cannot just ORDER BY
> uu.add_date,
> > because I do not have uu.add_date in the SELECT part of the
> statement.
>
> Sure you can. Back around SQL89 there was a restriction that ORDER
> BY
> values had to appear in the SELECT list as well, but no modern
> database
> has such a restriction anymore ...
>
> regards, tom lane