Re: sum() over (partition by order) question

2008/12/31 Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>:
> "Pavel Stehule" <pavel(dot)stehule(at)gmail(dot)com> writes:
>> so I have to modify query to get expected values
>> postgres=# select a, b, last_value(a) over (partition by b),
>> last_value(a) over (partition by b order by a RANGE BETWEEN UNBOUNDED
>> PRECEDING AND UNBOUNDED FOLLOWING) from foo;
>
>> it should be noticed in doc?
>
> It is --- see the comments at the bottom of
>
> http://developer.postgresql.org/pgdocs/postgres/functions-window.html
>
> regards, tom lane
>

oh, yes, there it is, thank you
and Happy New Year

regards
Pavel Stehule