Re: [SQL] Ordering a date_part() query ...

From: Bruce Momjian <pgman(at)candle(dot)pha(dot)pa(dot)us>
To: Mark Volpe <volpe(dot)mark(at)epamail(dot)epa(dot)gov>
Cc: The Hermit Hacker <scrappy(at)hub(dot)org>, pgsql-sql(at)postgreSQL(dot)org
Subject: Re: [SQL] Ordering a date_part() query ...
Date: 2000-01-18 18:28:40
Message-ID: 200001181828.NAA05364@candle.pha.pa.us
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> The Hermit Hacker wrote:
> >
> > I have a query that looks like:
> >
> > SELECT ( date_part('month', stat_period) || '/' ||
> > date_part('day', stat_period) || '/' ||
> > date_part('year', stat_period) || ' ' ||
> > date_part('hour', stat_period) || ':00:00' ) as "Summary - by
> > Day/Hour",
> > sum(impressions) as impressions, sum(click_thru) as click_thru
> > FROM banner_count
> > GROUP BY "Summary - by Day/Hour";
> >
>
> Try appending ORDER BY "Summary - by Day/Hour"::date
> to your query.

Oh, much better than my CASE idea. I thought he was sorting date/time
strings, not datetime values.

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