Re: [SQL] Ordering a date_part() query ...

You may need to use CASE to output a column to be sorted on.

>
> I have a query that looks like:
>
> SELECT ( date_part('month', stat_period) || '/' ||
> date_part('day', stat_period) || '/' ||
> date_part('year', stat_period) || ' ' ||
> date_part('hour', stat_period) || ':00:00' ) as "Summary - by
> Day/Hour",
> sum(impressions) as impressions, sum(click_thru) as click_thru
> FROM banner_count
> GROUP BY "Summary - by Day/Hour";
>
>
> Works great, except that the output looks like:
>
> Summary - by Day/Hour|impressions|click_thru
> ---------------------+-----------+----------
> 1/17/2000 23:00:00 | 63| 1
> 1/18/2000 0:00:00 | 151| 0
> 1/18/2000 10:00:00 | 348| 4
> 1/18/2000 11:00:00 | 804| 1
> 1/18/2000 12:00:00 | 180| 1
> 1/18/2000 1:00:00 | 89| 0
> 1/18/2000 2:00:00 | 112| 0
> 1/18/2000 3:00:00 | 178| 0
> 1/18/2000 4:00:00 | 184| 0
> 1/18/2000 5:00:00 | 133| 0
> 1/18/2000 6:00:00 | 119| 0
> 1/18/2000 7:00:00 | 148| 0
> 1/18/2000 8:00:00 | 224| 0
> 1/18/2000 9:00:00 | 272| 0
>
> Notice the 10/11/12/etc hour stats come before the 1am stats?
>
> So its sorting okay on the date, but I need to get it to d it on the time
> as well..
>
> I'm still playing with it, but if someone can suggest a means of doing
> this, I'm all ears :)
>
> Thanks...
>
> Marc G. Fournier ICQ#7615664 IRC Nick: Scrappy
> Systems Administrator @ hub.org
> primary: scrappy(at)hub(dot)org secondary: scrappy(at){freebsd|postgresql}.org
>
>
> ************
>
>

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