From: | The Hermit Hacker <scrappy(at)hub(dot)org> |
---|---|
To: | Tamsin <tg_mail(at)bryncadfan(dot)co(dot)uk> |
Cc: | Dan Browning <danb(at)cyclonecomputers(dot)com>, pgsql-novice(at)postgresql(dot)org |
Subject: | RE: cat infile | translate all occurences of "NOT NULL" to "" |
Date: | 2000-09-11 14:53:31 |
Message-ID: | Pine.BSF.4.21.0009111153090.1305-100000@thelab.hub.org |
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Thread: | |
Lists: | pgsql-novice |
cat infile | sed 's/NOT NULL//g'
should do it as well ...
On Mon, 11 Sep 2000, Tamsin wrote:
> in vi you can type : and then 1,$s/oldstring/newstring/g
> where 1 means start from the first line, $ means until the end of the file,
> oldstring is what you want to replace, newstring is what you want to replace
> it with, and the g means do it globally throughout the file.
>
> e.g. 1,$s/NOT NULL//g should work
>
> Hope this helps
> Tamsin
>
> -----Original Message-----
> From: pgsql-novice-owner(at)hub(dot)org [mailto:pgsql-novice-owner(at)hub(dot)org]On
> Behalf Of Dan Browning
> Sent: 11 September 2000 15:16
> To: pgsql-novice(at)postgresql(dot)org; redhat-list(at)redhat(dot)com;
> jsokel(at)mdsi-usa(dot)com
> Subject: [NOVICE] cat infile | translate all occurences of "NOT NULL" to
> ""
>
>
> what command do I use to substitute all occurences of a certain string (say,
> "NOT NULL") with another arbitrary string, (e.g. "")? I've tried grep and
> tr, but can't figure it out.
>
> Thanks,
>
> Dan Browning
> Network & Database Administrator
> Cyclone Computer Systems
>
>
Marc G. Fournier ICQ#7615664 IRC Nick: Scrappy
Systems Administrator @ hub.org
primary: scrappy(at)hub(dot)org secondary: scrappy(at){freebsd|postgresql}.org
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