RE: [SQL] How do I do this queyr?

From: "Jackson, DeJuan" <djackson(at)cpsgroup(dot)com>
To: pierre(at)desertmoon(dot)com, pgsql-sql(at)postgreSQL(dot)org
Subject: RE: [SQL] How do I do this queyr?
Date: 1999-02-25 22:09:17
Message-ID: F10BB1FAF801D111829B0060971D839F6B4790@cpsmail
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try:
SELECT id FROM mytable t1
WHERE keyword='abc' AND
EXISTS(SELECT 1 FROM mytable t2
WHERE keyword ='def' AND t1.id = t2.id);

-DEJ

> -----Original Message-----
> From: pierre(at)desertmoon(dot)com [mailto:pierre(at)desertmoon(dot)com]
> Sent: Thursday, February 25, 1999 2:42 PM
> To: pgsql-sql(at)postgreSQL(dot)org
> Subject: [SQL] How do I do this queyr?
>
>
> All,
> Given a table of keywords. How would I grab the distinct
> id's that have
> both keywords attached to it. Example:
>
> ID | Keyword
> -------------
> 1 | abc
> 2 | abc
> 3 | def
> 1 | def
>
> We want all the id's that have BOTH abc AND def as
> keywords. I think I may
> be having a brain freeze here...it seems obvious but I just
> can't seem
> to get my brain to spit up the answer. :( Too much caffiene?
>
> Thanks for the help!
>
> -=pierre
>

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