From: | Hubert Lubaczewski <hubert(dot)lubaczewski(at)eo(dot)pl> |
---|---|
To: | "Ryan" <pgsql-sql(at)seahat(dot)com> |
Cc: | <pgsql-sql(at)postgresql(dot)org> |
Subject: | Re: aggregate question |
Date: | 2003-06-24 07:33:22 |
Message-ID: | 20030624093322.2051cbb5.hubert.lubaczewski@eo.pl |
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Thread: | |
Lists: | pgsql-sql |
On Mon, 23 Jun 2003 13:59:52 -0500 (CDT)
"Ryan" <pgsql-sql(at)seahat(dot)com> wrote:
> package_id | integer | not null default
> I must be a total space case today because I can't hammer out the sql to
> get a listing of all the packages with a count() of the package_log by
> package_id.
if you would just package_id and count it would be simple:
select
p.package_id,
count(*) as count
from
packages p
left outer join package_log l on p.package_id = l.package_id
;
but, if you want all fields from packages it get trickier.
you can do it in two ways:
select
p.*,
(select count(*) from package_log l where l.package_id = p.package_id)
from
packages p
or:
select
p.*,
coalesce(c.count,0)
from
packages p
left outer join (select l.package_id, count(*) as count from package_log l) c on p.package_id = c.package_id
should work - but i just wrote it "by hand", and didn't test it. anyway - it should give either working code or idea on how to achieve it.
depesz
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