Re: [HACKERS] =ANY bug

From: Bruce Momjian <maillist(at)candle(dot)pha(dot)pa(dot)us>
To: sferac(at)bo(dot)nettuno(dot)it
Cc: pgsql-hackers(at)postgreSQL(dot)org, vadim(at)sable(dot)krasnoyarsk(dot)su (Vadim B(dot) Mikheev)
Subject: Re: [HACKERS] =ANY bug
Date: 1998-12-13 04:21:43
Message-ID: 199812130421.XAA13936@candle.pha.pa.us
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> Hi all,
>
> Because IN is semantically identical to =ANY
> here the same error using ANY:
>
> select * from emp where ename =ANY (
> select ename from emp group by ename having 1 < count(ename)
> );

Can I just say that using HAVING inside a subquery is buggy? Vadim, was
this already fixed?

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In response to

  • =ANY bug at 1998-12-03 15:06:36 from Sferacarta Software

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