On Thu, Apr 29, 2010 at 8:52 AM, Thom Brown <thombrown(at)gmail(dot)com> wrote:
> On 29 April 2010 13:35, Bård Grønbech <baard(dot)gronbech(at)gmail(dot)com> wrote:
>> Have a string like '0.1;0.2;null;0.3' which I would like to convert
>> into a double precision array.
>> select cast (string_to_array('0.1;0.2;null;0.3', ';') as float8)
>> gives me an error: invalid input syntax for type double precision: "null".
>> Can anybody help me?
> I believe string_to_array will take that null as a string called 'null',
> which it can't convert to a float8.
select array(select case when n='null' then null else n end from
unnest(string_to_array('0.1;0.2;null;0.3', ';')) as n);
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