BUG #6609: pattern matching (version 8.2 or so...)

From: biju(dot)george(at)ust-global(dot)com
To: pgsql-bugs(at)postgresql(dot)org
Subject: BUG #6609: pattern matching (version 8.2 or so...)
Date: 2012-04-23 15:16:40
Message-ID: E1SML0K-0007Bo-TH@wrigleys.postgresql.org
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The following bug has been logged on the website:

Bug reference: 6609
Logged by: biju george
Email address: biju(dot)george(at)ust-global(dot)com
PostgreSQL version: Unsupported/Unknown
Operating system: Linux
Description:

I have a text column which have values like
'01abcd','012345','abcde',etc...
Now I am trying to take the first 2 characters of the column and pass into a
function which takes only integer values and returns an integer. So, I need
to check before I input into the function whether the substring is integer
or not. If integer then the return value else default value say 99.
select my_function(case when substr(my_column,1,2) like '[0-9][0-9]' then
substr(my_column,1,2) else 99 end) from my_table;
I tried like, =, ~. Nothing seems to work. Tried ::text, ::integer and
all...

It always throws error --
ERROR: CASE types integer and text cannot be matched

The darn thing just don't work... :mad:

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