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Re: query with =ALL

From: "Jaime Casanova" <el_vigia_ec(at)hotmail(dot)com>
To: pgsql-sql(at)postgresql(dot)org
Subject: Re: query with =ALL
Date: 2004-06-14 18:06:37
Message-ID: BAY8-F51dXvTmtTruAV0007a81b@hotmail.com (view raw or flat)
Thread:
Lists: pgsql-sql
On Mon, 14 Jun 2004, Jaime Casanova wrote:

 > i have an strange result here, i'm using 7.4.2 on redhat 8
 >
 > i have a query like this
 >
 > SELECT CPA.rub_codigo, RUB.rub_descripcion, CPA.cpa_valor,
 > CPA.cpa_fechavencimiento
 > FROM rec_m_cuadropagos CPA, rec_m_rubro RUB
 > WHERE RUB.ent_codigo = CPA.ent_codigo AND RUB.rub_codigo = CPA.rub_codigo
 > AND
 >       CPA.ent_codigo = 1 AND CPA.sec_codigo = 1 AND CPA.ani_codigo =
 > '2004-2005' AND
 >       CPA.cic_codigo = 1 AND CPA.esp_codigo = 0 AND CPA.cur_codigo = 1 
AND
 >       CPA.cur_paralelo = ALL (SELECT cur_paralelo FROM aca_t_curso WHERE
 > ent_codigo = 1 AND
 >
 > sec_codigo = 1 AND
 >
 > ani_codigo = '2004-2005' AND
 >
 > cic_codigo = 1 AND
 >
 > esp_codigo = 0 AND
 >
 > cur_codigo = 1)
 >
 > that bring no values but if i do this (the same query without the =ALL 
part)
 >
 > SELECT CPA.rub_codigo, RUB.rub_descripcion, CPA.cpa_valor,
 > CPA.cpa_fechavencimiento
 > FROM rec_m_cuadropagos CPA, rec_m_rubro RUB
 > WHERE RUB.ent_codigo = CPA.ent_codigo AND RUB.rub_codigo = CPA.rub_codigo
 > AND
 >       CPA.ent_codigo = 1 AND CPA.sec_codigo = 1 AND CPA.ani_codigo =
 > '2004-2005' AND
 >       CPA.cic_codigo = 1 AND CPA.esp_codigo = 0 AND CPA.cur_codigo = 1
 >
 > get a resultset, one would think that the =ALL subquery is filtering out
 > that rows but the cur_paralelo has same values in both sides
 >
 > select distinct cur_paralelo from rec_m_cuadropagos WHERE ent_codigo = 1 
AND
 >
 > sec_codigo = 1 AND
 >
 > ani_codigo = '2004-2005' AND
 >
 > cic_codigo = 1 AND
 >
 > esp_codigo = 0 AND
 >
 > cur_codigo = 1
 > intersect
 > SELECT cur_paralelo FROM aca_t_curso WHERE ent_codigo = 1 AND
 >
 > sec_codigo = 1 AND
 >
 > ani_codigo = '2004-2005' AND
 >
 > cic_codigo = 1 AND
 >
 > esp_codigo = 0 AND
 >
 > cur_codigo = 1
 >
 > this query proves that its result is 'A', 'B', 'C'
 >
 > any idea, is something wrong in my thinking?

AFAIK, The query isn't check all values that meet the other criteria
against all values of the subquery but instead check the value from each
row that meets the other criteria against all the values in the subquery.
If the values in the subquery are distinct, it's not going to return true.


Is there another solution instead the one i'm using can you help me in that?

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Subject: Re: max value from join
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Subject: Re: query with =ALL

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