> # Avoid bug that converts 'x =- 1' to 'x = -1'
> $source =~ s!=- !-= !g;
I haven't looked at the shell script this replaces, but is that the correct substitution pattern? (BTW, I'm not seeing the token =- anywhere except in the Makefile, which wouldn't be run against, no? Am I missing something?)
Regards,
David
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David Christensen
End Point Corporation
david(at)endpoint(dot)com