Re: Interval output format

At 13:37 18.01.2001 -0500, Tom Lane wrote:
>"Stefan Waidele jun." <St(dot)Waidele(dot)jun(at)Krone-Neuenburg(dot)de> writes:
> > How can I tell Postgres to return an interval value in an format like
> hhh:mm?
>
>See to_char(),
>http://www.postgresql.org/devel-corner/docs/postgres/functions-formatting.htm
>
> regards, tom lane

Thanks Tom,

I have been at this page before and did not get a clue.
Have I overlooked something? (Note: I am using an interval, not a date)
It would be great to have an example, since to_char('1 14:30', 'hh:mm')
(and others) gave me errors.

On the next page I have found dat_part(), and solved my problem using:
select date_part('day', sum(gearbeitet))*24+date_part('hour',
sum(gearbeitet))||':'||date_part('min', sum(gearbeitet)) from stunden;

But here comes the next problem:
When I tried to do a SQL-Function

create function sum_gearbeitet(text)
returns text
as "select
date_part('day',sum(gearbeitet))*24+date_part('hour',sum(gearbeitet))||':'||date_part('min',sum(gearbeitet))
from stunden;"
language 'sql';

psql said:

NOTICE: identifier "select
date_part('day',sum(gearbeitet))*24+date_part('hour',sum(gearbeitet))||':'||date_part('min',sum(gearbeitet))
from stunden;" will be truncated to "select date_part('day',sum(gear"
ERROR: parser: parse error at or near """

What am I doing wrong? (shorter functions are also truncated)

Stefan