Am 20.05.2012 05:04, schrieb Jasen Betts:
> On 2012-05-19, Andreas<maps(dot)on(at)gmx(dot)net> wrote:
>> I'm trying to fight against double entries in tables.
>> I got as far as I can find similar records with trigram string matching.
>> If I do this with a table compared to itself I get something like this:
>> id_a, id_b
>> 3, 5
>> 3, 7
>> 5, 3
>> 5, 7
>> 7, 3
>> 7, 5
>> 11, 13
>> 13, 11
>> so the records with the IDs 3, 5, 7 and 11, 13 are similar enough to
>> form a group.
>> How would I get a list of record-IDs with a group-ID like this
>> record_id, group_id
>> 3, 1
>> 5, 1
>> 7, 1
>> 11, 2
>> 13, 2
>> Is there a way to get this by SQL ?
> select id_a,min(least(id_a,id_b)) from SOMETHING group by id_a
> close enough?
> or this: ?
> select id_a, rank() over order by g from
> ( select id_a,min(least(id_a,id_b)) as g from SOMETHING group by id_a ) as foo
Thats by far more elegant as my approach with arrays I figured out in
I changed rank() to dense_rank() in your solution.
Functionally the 1st line does allready all the magic, though.
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